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One can calculate the 95% confidence interval for the mean with the population standard deviation known. This will give us an upper and a lower confidence limit. What happens if we decide to calculate the 99% confidence interval? Describe how the increase in the confidence level has changed the width of the confidence interval. Do the same for the confidence interval set at 90%. Do an example and give real values for the intervals in your post.Β  The formula for a confidence interval is:xΜ„ +/- zΞ±/2 βˆ™Οƒ/ sqrt(n)Β Β Β Β  Use that formula with the numbers plugged into it.Β xΜ„ is the sample mean and n is the sample size (no. of samples collected). The population standard deviation is denoted by the greek letter sigma Οƒ:(1-Ξ±)*100% Β is the level of confidence.For example, in a 95% confidence intervalΒ 1- Ξ± =.95Β Solving for Ξ± givesΒ Ξ± =.05(Also, see Table 8.1 on page 359, under 95% confidence). Thus:Β Ξ±/2 = .05/2 =.025zΞ±/2Β  denotes the z value on the bell-shaped curve whose right-tail area isΒ Ξ±/2 .For example, on page 292 (under “what is this z value?”), the z value there is denoted byΒ z.10Β since the right-tail area of that z value is .10.If you are doing a 95% confidence interval for the mean using formula 8.1 on page 358, thenΒ zΞ±/2 =Β z.025Β  = 1.96by looking up the z-value on table 8.1 on page 359 (under confidence level 95%). This means that the area to the right of z=1.96 is .025.

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